C program to print inverted pattern of numbers
Source code:
#include "stdio.h"
int main()
{
int i,j,n=5;
for(i=0;i<=4;i++)
{
for(j=1;j<=9;j++)
{
if(i>j)
{
printf(" ");
}
else if(i+j==10)
{
printf(" ");
break;
}
else if(i==j)
{
printf(" ");
}
else
{
printf("%d",j);
}
}
printf("\n");
}
return(0);
}

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